What is the integral of (e^x-1/(7x)) ?

The integral of (e^x-1/(7x)) is e^x-1/7 ln|x|+C

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integral of (e^x-1/(7x))

\int (e^{x} - \frac{1}{7 x}) d x

e^{x} - \frac{1}{7} ln ∣ x ∣ + C

Solution steps

\int e^{x} - \frac{1}{7 x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int e^{x} d x - \int \frac{1}{7 x} d x

\int e^{x} d x = e^{x}

\int \frac{1}{7 x} d x = \frac{1}{7} ln ∣ x ∣

= e^{x} - \frac{1}{7} ln ∣ x ∣

Add a constant to the solution

= e^{x} - \frac{1}{7} ln ∣ x ∣ + C

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What is the integral of (e^x-1/(7x)) ?
The integral of (e^x-1/(7x)) is e^x-1/7 ln|x|+C