What is the integral of θtan(2)θ^2 ?

The integral of θtan(2)θ^2 is 1/4 tan(2)θ^4+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of θtan(2)θ^2

\int θ tan (2) θ^{2} d θ

\frac{1}{4} tan (2) θ^{4} + C

Solution steps

\int θ tan (2) θ^{2} d θ

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= tan (2) \cdot \int θ θ^{2} d θ

Simplify

θ θ^{2} : θ^{3}

= tan (2) \cdot \int θ^{3} d θ

Apply the Power Rule

: \frac{θ ^{4}}{4}

= tan (2) \frac{θ ^{4}}{4}

Simplify

tan (2) \frac{θ ^{4}}{4} : \frac{1}{4} tan (2) θ^{4}

= \frac{1}{4} tan (2) θ^{4}

Add a constant to the solution

= \frac{1}{4} tan (2) θ^{4} + C

\int \frac{- x}{x ^{2} - x + 1} d x

\int \frac{x}{25 x ^{4} + 9} d x

\int \frac{1}{5 + 4 sin ( 2 x )} d x

\int \frac{4 x - 3}{( x - 2 ) ( x ^{2} + 1 )} d x

\int (12 x + 2) tan (15 x^{2} + 5 x) d x

What is the integral of θtan(2)θ^2 ?
The integral of θtan(2)θ^2 is 1/4 tan(2)θ^4+C