What is the integral of 1/((x^2+1)) ?

The integral of 1/((x^2+1)) is arctan(x)+C

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integral of 1/((x^2+1))

integral

\frac{1}{( x ^{2} + 1 )}

arctan (x) + C

Solution steps

\int \frac{1}{x ^{2} + 1} d x

Use the common integral:

\int \frac{1}{x ^{2} + 1} d x = arctan (x)

= arctan (x)

Add a constant to the solution

= arctan (x) + C

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What is the integral of 1/((x^2+1)) ?
The integral of 1/((x^2+1)) is arctan(x)+C