What is the integral of (x^2+11x)/((x+1)^2(x-1)) ?

The integral of (x^2+11x)/((x+1)^2(x-1)) is -2ln|x+1|-5/(x+1)+3ln|x-1|+C

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integral of (x^2+11x)/((x+1)^2(x-1))

\int \frac{x ^{2} + 11 x}{( x + 1 ) ^{2} ( x - 1 )} d x

- 2 ln ∣ x + 1 ∣ - \frac{5}{x + 1} + 3 ln ∣ x - 1 ∣ + C

Solution steps

\int \frac{x ^{2} + 11 x}{( x + 1 ) ^{2} ( x - 1 )} d x

Take the partial fraction of

\frac{x ^{2} + 11 x}{( x + 1 ) ^{2} ( x - 1 )} : - \frac{2}{x + 1} + \frac{5}{( x + 1 ) ^{2}} + \frac{3}{x - 1}

= \int - \frac{2}{x + 1} + \frac{5}{( x + 1 ) ^{2}} + \frac{3}{x - 1} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int \frac{2}{x + 1} d x + \int \frac{5}{( x + 1 ) ^{2}} d x + \int \frac{3}{x - 1} d x

\int \frac{2}{x + 1} d x = 2 ln ∣ x + 1 ∣

\int \frac{5}{( x + 1 ) ^{2}} d x = - \frac{5}{x + 1}

\int \frac{3}{x - 1} d x = 3 ln ∣ x - 1 ∣

= - 2 ln ∣ x + 1 ∣ - \frac{5}{x + 1} + 3 ln ∣ x - 1 ∣

Add a constant to the solution

= - 2 ln ∣ x + 1 ∣ - \frac{5}{x + 1} + 3 ln ∣ x - 1 ∣ + C

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What is the integral of (x^2+11x)/((x+1)^2(x-1)) ?
The integral of (x^2+11x)/((x+1)^2(x-1)) is -2ln|x+1|-5/(x+1)+3ln|x-1|+C