What is the integral of cos^3(z) ?

The integral of cos^3(z) is sin(z)-(sin^3(z))/3+C

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integral of cos^3(z)

\int cos^{3} (z) d z

sin (z) - \frac{sin ^{3} ( z )}{3} + C

Solution steps

\int cos^{3} (z) d z

Rewrite using trig identities

= \int (1 - sin^{2} (z)) cos (z) d z

Apply u-substitution

: \int 1 - u^{2} d u

= \int 1 - u^{2} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d u - \int u^{2} d u

\int 1 d u = u

\int u^{2} d u = \frac{u ^{3}}{3}

= u - \frac{u ^{3}}{3}

Substitute back

u = sin (z)

= sin (z) - \frac{sin ^{3} ( z )}{3}

Add a constant to the solution

= sin (z) - \frac{sin ^{3} ( z )}{3} + C

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What is the integral of cos^3(z) ?
The integral of cos^3(z) is sin(z)-(sin^3(z))/3+C