What is the integral of (8sqrt(x)-9) ?

The integral of (8sqrt(x)-9) is 16/3 x^{3/2}-9x+C

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integral of (8sqrt(x)-9)

\int (8 x - 9) d x

\frac{16}{3} x^{\frac{3}{2}} - 9 x + C

Solution steps

\int 8 x - 9 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 8 x d x - \int 9 d x

\int 8 x d x = \frac{16}{3} x^{\frac{3}{2}}

\int 9 d x = 9 x

= \frac{16}{3} x^{\frac{3}{2}} - 9 x

Add a constant to the solution

= \frac{16}{3} x^{\frac{3}{2}} - 9 x + C

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What is the integral of (8sqrt(x)-9) ?
The integral of (8sqrt(x)-9) is 16/3 x^{3/2}-9x+C