What is the derivative of f(x)=10x^2+10x+8+ln(x) ?

The derivative of f(x)=10x^2+10x+8+ln(x) is 20x+1/x+10

What is the first derivative of f(x)=10x^2+10x+8+ln(x) ?

The first derivative of f(x)=10x^2+10x+8+ln(x) is 20x+1/x+10

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derivative of

f (x) = 10 x^{2} + 10 x + 8 + ln (x)

20 x + \frac{1}{x} + 10

Solution steps

\frac{d}{d x} (10 x^{2} + 10 x + 8 + ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (10 x^{2}) + \frac{d}{d x} (10 x) + \frac{d}{d x} (8) + \frac{d}{d x} (ln (x))

\frac{d}{d x} (10 x^{2}) = 20 x

\frac{d}{d x} (10 x) = 10

\frac{d}{d x} (8) = 0

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 20 x + 10 + 0 + \frac{1}{x}

Simplify

= 20 x + \frac{1}{x} + 10

y^{^{''}} + 9 y = cos (6 t)

x \to 2 - lim (2)

y = arctan (- 2 x), at x = - 3

\int 14 e^{x} d x

f (x) = 1 - 6 x^{2}, (2, - 23)

What is the derivative of f(x)=10x^2+10x+8+ln(x) ?
The derivative of f(x)=10x^2+10x+8+ln(x) is 20x+1/x+10
What is the first derivative of f(x)=10x^2+10x+8+ln(x) ?
The first derivative of f(x)=10x^2+10x+8+ln(x) is 20x+1/x+10