What is the integral of (ln^2(y))/y ?

The integral of (ln^2(y))/y is (ln^3(y))/3+C

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integral of (ln^2(y))/y

\int \frac{ln ^{2} ( y )}{y} d y

\frac{ln ^{3} ( y )}{3} + C

Solution steps

\int \frac{ln ^{2} ( y )}{y} d y

Apply u-substitution

: \int u^{2} d u

= \int u^{2} d u

Apply the Power Rule

: \frac{u ^{3}}{3}

= \frac{u ^{3}}{3}

Substitute back

u = ln (y)

= \frac{ln ^{3} ( y )}{3}

Add a constant to the solution

= \frac{ln ^{3} ( y )}{3} + C

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What is the integral of (ln^2(y))/y ?
The integral of (ln^2(y))/y is (ln^3(y))/3+C