What is the integral of e^{(3x)/5} ?

The integral of e^{(3x)/5} is 5/3 e^{(3x)/5}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{(3x)/5}

\int e^{\frac{3 x}{5}} d x

\frac{5}{3} e^{\frac{3 x}{5}} + C

Solution steps

\int e^{\frac{3 x}{5}} d x

Apply u-substitution

: \int e^{u} \frac{5}{3} d u

= \int e^{u} \frac{5}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{5}{3} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{5}{3} e^{u}

Substitute back

u = \frac{3 x}{5}

= \frac{5}{3} e^{\frac{3 x}{5}}

Add a constant to the solution

= \frac{5}{3} e^{\frac{3 x}{5}} + C

\int cos^{4} (w) d w

\int 3 x^{2} (x^{3} + 2)^{4} d x

\int (4 - x^{2})^{3} d x

\int r cos (θ) d r

\int e^{- s t} e^{t} d t

What is the integral of e^{(3x)/5} ?
The integral of e^{(3x)/5} is 5/3 e^{(3x)/5}+C