What is the solution for (dy)/(dx)=x^2-y-2,y(0)=-1 ?

The solution for (dy)/(dx)=x^2-y-2,y(0)=-1 is y=x^2-2x-1/(e^x)

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(dy)/(dx)=x^2-y-2,y(0)=-1

\frac{d y}{d x} = x^{2} - y - 2, y (0) = - 1

y = x^{2} - 2 x - \frac{1}{e ^{x}}

Solution steps

\frac{d y}{d x} = x^{2} - y - 2

Solve linear ODE:

y = x^{2} - 2 x - \frac{1}{e ^{x}}

y = x^{2} - 2 x - \frac{1}{e ^{x}}

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What is the solution for (dy)/(dx)=x^2-y-2,y(0)=-1 ?
The solution for (dy)/(dx)=x^2-y-2,y(0)=-1 is y=x^2-2x-1/(e^x)