What is the integral of 1 (ln(x)) ?

The integral of 1 (ln(x)) is d(xln(x)-x)+C

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integral of 1 (ln(x))

\int \frac{d}{1} (ln (x)) d x

d (x ln (x) - x) + C

Solution steps

\int \frac{d}{1} ln (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= d \cdot \int ln (x) d x

Apply Integration By Parts

: x ln (x) - \int 1 d x

= d (x ln (x) - \int 1 d x)

\int 1 d x = x

= d (x ln (x) - x)

Add a constant to the solution

= d (x ln (x) - x) + C

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