What is the integral of 2x^3-3x^2 ?

The integral of 2x^3-3x^2 is (x^4)/2-x^3+C

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integral of 2x^3-3x^2

\int 2 x^{3} - 3 x^{2} d x

\frac{x ^{4}}{2} - x^{3} + C

Solution steps

\int 2 x^{3} - 3 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x^{3} d x - \int 3 x^{2} d x

\int 2 x^{3} d x = \frac{x ^{4}}{2}

\int 3 x^{2} d x = x^{3}

= \frac{x ^{4}}{2} - x^{3}

Add a constant to the solution

= \frac{x ^{4}}{2} - x^{3} + C

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