What is the derivative of y=3x^2+5 ?

The derivative of y=3x^2+5 is 6x

What is the first derivative of y=3x^2+5 ?

The first derivative of y=3x^2+5 is 6x

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derivative of

y = 3 x^{2} + 5

6 x

Solution steps

\frac{d}{d x} (3 x^{2} + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (5)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (5) = 0

= 6 x + 0

Simplify

= 6 x

\int \frac{2}{5 cos ^{2} ( x )} d x

\int sec (2 x) tan^{3} (2 x) d x

e^{\frac{x ^{2}}{2}}

\int_{0}^{\frac{π}{8}} sin^{2} (2 x) d x

sin (x) cos (x)

What is the derivative of y=3x^2+5 ?
The derivative of y=3x^2+5 is 6x
What is the first derivative of y=3x^2+5 ?
The first derivative of y=3x^2+5 is 6x