What is the integral of e^{2y}y ?

The integral of e^{2y}y is 1/4 (e^{2y}*2y-e^{2y})+C

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integral of e^{2y}y

\int e^{2 y} y d y

\frac{1}{4} (e^{2 y} \cdot 2 y - e^{2 y}) + C

Solution steps

\int e^{2 y} y d y

Apply u-substitution

: \int \frac{e ^{u} u}{4} d u

= \int \frac{e ^{u} u}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int e^{u} u d u

Apply Integration By Parts

: e^{u} u - \int e^{u} d u

= \frac{1}{4} (e^{u} u - \int e^{u} d u)

\int e^{u} d u = e^{u}

= \frac{1}{4} (e^{u} u - e^{u})

Substitute back

u = 2 y

= \frac{1}{4} (e^{2 y} \cdot 2 y - e^{2 y})

Add a constant to the solution

= \frac{1}{4} (e^{2 y} \cdot 2 y - e^{2 y}) + C

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What is the integral of e^{2y}y ?
The integral of e^{2y}y is 1/4 (e^{2y}*2y-e^{2y})+C