What is the integral of (5x)/(x^3+x^2) ?

The integral of (5x)/(x^3+x^2) is 5(ln|x|-ln|x+1|)+C

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integral of (5x)/(x^3+x^2)

\int \frac{5 x}{x ^{3} + x ^{2}} d x

5 (ln ∣ x ∣ - ln ∣ x + 1 ∣) + C

Solution steps

\int \frac{5 x}{x ^{3} + x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int \frac{x}{x ^{3} + x ^{2}} d x

Take the partial fraction of

\frac{x}{x ^{3} + x ^{2}} : \frac{1}{x} - \frac{1}{x + 1}

= 5 \cdot \int \frac{1}{x} - \frac{1}{x + 1} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 5 (\int \frac{1}{x} d x - \int \frac{1}{x + 1} d x)

\int \frac{1}{x} d x = ln ∣ x ∣

\int \frac{1}{x + 1} d x = ln ∣ x + 1 ∣

= 5 (ln ∣ x ∣ - ln ∣ x + 1 ∣)

Add a constant to the solution

= 5 (ln ∣ x ∣ - ln ∣ x + 1 ∣) + C

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What is the integral of (5x)/(x^3+x^2) ?
The integral of (5x)/(x^3+x^2) is 5(ln|x|-ln|x+1|)+C