What is the integral of (x^4+2x-5) ?

The integral of (x^4+2x-5) is (x^5)/5+x^2-5x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (x^4+2x-5)

\int (x^{4} + 2 x - 5) d x

\frac{x ^{5}}{5} + x^{2} - 5 x + C

Solution steps

\int x^{4} + 2 x - 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{4} d x + \int 2 x d x - \int 5 d x

\int x^{4} d x = \frac{x ^{5}}{5}

\int 2 x d x = x^{2}

\int 5 d x = 5 x

= \frac{x ^{5}}{5} + x^{2} - 5 x

Add a constant to the solution

= \frac{x ^{5}}{5} + x^{2} - 5 x + C

\int e^{s e c (2 x)} sec (2 x) tan (2 x) d x

\int \frac{1}{( 3 x - 1 ) ^{6}} d x

\int \frac{8 x}{x ^{2} + 3} d x

\int \frac{2 x ^{2} + 2 x}{x ^{3} - x ^{2} + x - 1} d x

What is the integral of (x^4+2x-5) ?
The integral of (x^4+2x-5) is (x^5)/5+x^2-5x+C