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Popular >

integral of sin(17x)

Solution

\int sin (17 x) d x

Solution

- \frac{1}{17} cos (17 x) + C

Solution steps

\int sin (17 x) d x

Apply u-substitution

: \int sin (u) \frac{1}{17} d u

= \int sin (u) \frac{1}{17} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{17} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{17} (- cos (u))

Substitute back

u = 17 x

= \frac{1}{17} (- cos (17 x))

Simplify

= - \frac{1}{17} cos (17 x)

Add a constant to the solution

= - \frac{1}{17} cos (17 x) + C

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\int \frac{2}{3 ^{- 2 x}} d x

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\int 60 x^{- \frac{1}{5}} tan (x^{\frac{4}{5}}) d x

integral of 1/(x^2(9x^2+1))

\int \frac{1}{x ^{2} ( 9 x ^{2} + 1 )} d x

Frequently Asked Questions (FAQ)

What is the integral of sin(17x) ?
The integral of sin(17x) is -1/17 cos(17x)+C