What is the integral of e^z+(y^2)/x ?

The integral of e^z+(y^2)/x is (y^2)/x z+e^z+C

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integral of e^z+(y^2)/x

\int e^{z} + \frac{y ^{2}}{x} d z

\frac{y ^{2}}{x} z + e^{z} + C

Solution steps

\int e^{z} + \frac{y ^{2}}{x} d z

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{y ^{2}}{x} d z + \int e^{z} d z

\int \frac{y ^{2}}{x} d z = \frac{y ^{2}}{x} z

\int e^{z} d z = e^{z}

= \frac{y ^{2}}{x} z + e^{z}

Add a constant to the solution

= \frac{y ^{2}}{x} z + e^{z} + C

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What is the integral of e^z+(y^2)/x ?
The integral of e^z+(y^2)/x is (y^2)/x z+e^z+C