What is (\partial)/(\partial x)(e^x+y^2) ?

The answer to (\partial)/(\partial x)(e^x+y^2) is e^x

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(\partial)/(\partial x)(e^x+y^2)

\frac{\partial}{\partial x} (e^{x} + y^{2})

e^{x}

Solution steps

\frac{\partial}{\partial x} (e^{x} + y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (e^{x}) + \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (e^{x}) = e^{x}

\frac{\partial}{\partial x} (y^{2}) = 0

= e^{x} + 0

Simplify

= e^{x}

\frac{d}{d x} ((cos (9 x))^{x})

\int \frac{x + 1 - 1}{x + 1 + 1} d x

y = 1 9^{x}

\int \frac{2 y}{y ^{2} + 1} d y

x \to 0 - lim (\frac{2}{3} x^{- \frac{1}{3}})

What is (\partial)/(\partial x)(e^x+y^2) ?
The answer to (\partial)/(\partial x)(e^x+y^2) is e^x