What is the integral of |x-6| ?

The integral of |x-6| is ((x-6)|x-6|)/2+C

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integral of |x-6|

\int ∣ x - 6 ∣ d x

\frac{( x - 6 ) ∣ x - 6 ∣}{2} + C

Solution steps

\int ∣ x - 6 ∣ d x

Apply u-substitution

: \int ∣ u ∣ d u

= \int ∣ u ∣ d u

Use the common integral:

\int ∣ u ∣ d u = \frac{u ∣ u ∣}{2}

= \frac{u ∣ u ∣}{2}

Substitute back

u = x - 6

= \frac{( x - 6 ) ∣ x - 6 ∣}{2}

Add a constant to the solution

= \frac{( x - 6 ) ∣ x - 6 ∣}{2} + C

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