What is the integral of 1-4/3 x^{1/3} ?

The integral of 1-4/3 x^{1/3} is x-x^{4/3}+C

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integral of 1-4/3 x^{1/3}

\int 1 - \frac{4}{3} x^{\frac{1}{3}} d x

x - x^{\frac{4}{3}} + C

Solution steps

\int 1 - \frac{4}{3} x^{\frac{1}{3}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d x - \int \frac{4}{3} x^{\frac{1}{3}} d x

\int 1 d x = x

\int \frac{4}{3} x^{\frac{1}{3}} d x = x^{\frac{4}{3}}

= x - x^{\frac{4}{3}}

Add a constant to the solution

= x - x^{\frac{4}{3}} + C

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What is the integral of 1-4/3 x^{1/3} ?
The integral of 1-4/3 x^{1/3} is x-x^{4/3}+C