What is the integral of y^{-3}+1/x ?

The integral of y^{-3}+1/x is ln|x|+x/(y^3)+C

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integral of y^{-3}+1/x

\int y^{- 3} + \frac{1}{x} d x

ln ∣ x ∣ + \frac{x}{y ^{3}} + C

Solution steps

\int y^{- 3} + \frac{1}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{x} d x + \int y^{- 3} d x

\int \frac{1}{x} d x = ln ∣ x ∣

\int y^{- 3} d x = \frac{x}{y ^{3}}

= ln ∣ x ∣ + \frac{x}{y ^{3}}

Add a constant to the solution

= ln ∣ x ∣ + \frac{x}{y ^{3}} + C

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What is the integral of y^{-3}+1/x ?
The integral of y^{-3}+1/x is ln|x|+x/(y^3)+C