What is the integral of 16-3x^2-2x ?

The integral of 16-3x^2-2x is 16x-x^3-x^2+C

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integral of 16-3x^2-2x

\int 16 - 3 x^{2} - 2 x d x

16 x - x^{3} - x^{2} + C

Solution steps

\int 16 - 3 x^{2} - 2 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 16 d x - \int 3 x^{2} d x - \int 2 x d x

\int 16 d x = 16 x

\int 3 x^{2} d x = x^{3}

\int 2 x d x = x^{2}

= 16 x - x^{3} - x^{2}

Add a constant to the solution

= 16 x - x^{3} - x^{2} + C

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What is the integral of 16-3x^2-2x ?
The integral of 16-3x^2-2x is 16x-x^3-x^2+C