What is the integral of (3sin(x)-2sec^2(x)) ?

The integral of (3sin(x)-2sec^2(x)) is -3cos(x)-2tan(x)+C

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integral of (3sin(x)-2sec^2(x))

\int (3 sin (x) - 2 sec^{2} (x)) d x

- 3 cos (x) - 2 tan (x) + C

Solution steps

\int 3 sin (x) - 2 sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 sin (x) d x - \int 2 sec^{2} (x) d x

\int 3 sin (x) d x = - 3 cos (x)

\int 2 sec^{2} (x) d x = 2 tan (x)

= - 3 cos (x) - 2 tan (x)

Add a constant to the solution

= - 3 cos (x) - 2 tan (x) + C

\int 27 d x

e^{- 5 x}

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\int \frac{( 4 + u )}{u} d u

What is the integral of (3sin(x)-2sec^2(x)) ?
The integral of (3sin(x)-2sec^2(x)) is -3cos(x)-2tan(x)+C