What is the integral of (6x-13)^{10} ?

The integral of (6x-13)^{10} is 1/66 (6x-13)^{11}+C

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integral of (6x-13)^{10}

\int (6 x - 13)^{10} d x

\frac{1}{66} (6 x - 13)^{11} + C

Solution steps

\int (6 x - 13)^{10} d x

Apply u-substitution

: \int \frac{u ^{10}}{6} d u

= \int \frac{u ^{10}}{6} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{6} \cdot \int u^{10} d u

Apply the Power Rule

: \frac{u ^{11}}{11}

= \frac{1}{6} \cdot \frac{u ^{11}}{11}

Substitute back

u = 6 x - 13

= \frac{1}{6} \cdot \frac{( 6 x - 13 ) ^{11}}{11}

Simplify

\frac{1}{6} \cdot \frac{( 6 x - 13 ) ^{11}}{11} : \frac{1}{66} (6 x - 13)^{11}

= \frac{1}{66} (6 x - 13)^{11}

Add a constant to the solution

= \frac{1}{66} (6 x - 13)^{11} + C

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What is the integral of (6x-13)^{10} ?
The integral of (6x-13)^{10} is 1/66 (6x-13)^{11}+C