What is the integral of (2e^{arccos(x)})/(sqrt(1-x^2)) ?

The integral of (2e^{arccos(x)})/(sqrt(1-x^2)) is -2e^{arccos(x)}+C

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integral of (2e^{arccos(x)})/(sqrt(1-x^2))

\int \frac{2 e ^{a r c c o s (x)}}{1 - x ^{2}} d x

- 2 e^{a r c c o s (x)} + C

Solution steps

\int \frac{2 e ^{a r c c o s (x)}}{1 - x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{e ^{a r c c o s (x)}}{1 - x ^{2}} d x

Apply u-substitution

: \int - e^{u} d u

= 2 \cdot \int - e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 (- \int e^{u} d u)

Use the common integral:

\int e^{u} d u = e^{u}

= 2 (- e^{u})

Substitute back

u = arccos (x)

= 2 (- e^{a r c c o s (x)})

Simplify

= - 2 e^{a r c c o s (x)}

Add a constant to the solution

= - 2 e^{a r c c o s (x)} + C

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What is the integral of (2e^{arccos(x)})/(sqrt(1-x^2)) ?
The integral of (2e^{arccos(x)})/(sqrt(1-x^2)) is -2e^{arccos(x)}+C