What is the integral of 1/(2x^{1/3)} ?

The integral of 1/(2x^{1/3)} is 3/4 x^{2/3}+C

Popular >

integral of 1/(2x^{1/3)}

\int \frac{1}{2 x ^{\frac{1}{3}}} d x

\frac{3}{4} x^{\frac{2}{3}} + C

Solution steps

\int \frac{1}{2 x ^{\frac{1}{3}}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{x ^{\frac{1}{3}}} d x

Apply the Power Rule

: \frac{3}{2} x^{\frac{2}{3}}

= \frac{1}{2} \cdot \frac{3}{2} x^{\frac{2}{3}}

Simplify

\frac{1}{2} \cdot \frac{3}{2} x^{\frac{2}{3}} : \frac{3}{4} x^{\frac{2}{3}}

= \frac{3}{4} x^{\frac{2}{3}}

Add a constant to the solution

= \frac{3}{4} x^{\frac{2}{3}} + C

\int (2 y + 1)^{2} d y

\int \frac{x ^{5}}{( 5 - x ^{6} ) ^{2}} d x

\int \frac{x ^{2}}{x ^{3} - 5} d x

\int (3 x^{2} + 5 x)^{4} (6 x + 5) d x

\int \frac{e ^{9 x}}{e ^{9 x} + 6} d x

What is the integral of 1/(2x^{1/3)} ?
The integral of 1/(2x^{1/3)} is 3/4 x^{2/3}+C