What is the integral of cos^6(1/2)x ?

The integral of cos^6(1/2)x is (cos^6(1/2)x^2)/2+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of cos^6(1/2)x

\int cos^{6} (\frac{1}{2}) x d x

\frac{cos ^{6} ( \frac{1}{2} ) x ^{2}}{2} + C

Solution steps

\int cos^{6} (\frac{1}{2}) x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= cos^{6} (\frac{1}{2}) \cdot \int x d x

Apply the Power Rule

: \frac{x ^{2}}{2}

= cos^{6} (\frac{1}{2}) \frac{x ^{2}}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{cos ^{6} ( \frac{1}{2} ) x ^{2}}{2}

Add a constant to the solution

= \frac{cos ^{6} ( \frac{1}{2} ) x ^{2}}{2} + C

\int cos (3) (x) d x

\int \frac{w ^{2}}{16 - w ^{2}} d w

\int cot (37 x) d x

\int \frac{5}{( 3 - 5 z ) ^{20}} d z

\int z tan^{2} (z) d z

What is the integral of cos^6(1/2)x ?
The integral of cos^6(1/2)x is (cos^6(1/2)x^2)/2+C