What is the integral of ((x^2))/4 ?

The integral of ((x^2))/4 is (x^3)/(12)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of ((x^2))/4

\int \frac{( x ^{2} )}{4} d x

\frac{x ^{3}}{12} + C

Solution steps

\int \frac{x ^{2}}{4} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int x^{2} d x

Apply the Power Rule

: \frac{x ^{3}}{3}

= \frac{1}{4} \cdot \frac{x ^{3}}{3}

Simplify

\frac{1}{4} \cdot \frac{x ^{3}}{3} : \frac{x ^{3}}{12}

= \frac{x ^{3}}{12}

Add a constant to the solution

= \frac{x ^{3}}{12} + C

\int \frac{12 x ^{11}}{x ^{12} + 1} d x

\int cos (y) d y

\int x - x cos (x) d x

\int \frac{7 + 2 tan ( x )}{cos ^{2} ( x )} d x

\int \frac{1}{x + x - 1} d x