What is the integral of (12x^3+9x^2-4x-10) ?

The integral of (12x^3+9x^2-4x-10) is 3x^4+3x^3-2x^2-10x+C

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integral of (12x^3+9x^2-4x-10)

\int (12 x^{3} + 9 x^{2} - 4 x - 10) d x

3 x^{4} + 3 x^{3} - 2 x^{2} - 10 x + C

Solution steps

\int 12 x^{3} + 9 x^{2} - 4 x - 10 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 12 x^{3} d x + \int 9 x^{2} d x - \int 4 x d x - \int 10 d x

\int 12 x^{3} d x = 3 x^{4}

\int 9 x^{2} d x = 3 x^{3}

\int 4 x d x = 2 x^{2}

\int 10 d x = 10 x

= 3 x^{4} + 3 x^{3} - 2 x^{2} - 10 x

Add a constant to the solution

= 3 x^{4} + 3 x^{3} - 2 x^{2} - 10 x + C

\int (ln (x))^{- 2} d x

\int \frac{cos ^{4} ( x )}{x} d x

\int 4 x^{3} e^{9 x^{4}} d x

\int (x + 8) e^{x} d x

\int (sec^{2} (x) + sec (x) tan (x)) d x

What is the integral of (12x^3+9x^2-4x-10) ?
The integral of (12x^3+9x^2-4x-10) is 3x^4+3x^3-2x^2-10x+C