What is the integral of 1/(sqrt(x^4)) ?

The integral of 1/(sqrt(x^4)) is -1/x+C

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integral of 1/(sqrt(x^4))

\int \frac{1}{x ^{4}} d x

- \frac{1}{x} + C

Solution steps

\int \frac{1}{x ^{4}} d x

x^{4} = x^{2},

assuming

x \geq 0

= \int \frac{1}{x ^{2}} d x

Apply the Power Rule

: - \frac{1}{x}

= - \frac{1}{x}

Add a constant to the solution

= - \frac{1}{x} + C

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