What is the integral of (3x^2-7x+4)/x ?

The integral of (3x^2-7x+4)/x is (3x^2)/2-7x+4ln|x|+C

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integral of (3x^2-7x+4)/x

\int \frac{3 x ^{2} - 7 x + 4}{x} d x

\frac{3 x ^{2}}{2} - 7 x + 4 ln ∣ x ∣ + C

Solution steps

\int \frac{3 x ^{2} - 7 x + 4}{x} d x

Expand

\frac{3 x ^{2} - 7 x + 4}{x} : 3 x - 7 + \frac{4}{x}

= \int 3 x - 7 + \frac{4}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x d x - \int 7 d x + \int \frac{4}{x} d x

\int 3 x d x = \frac{3 x ^{2}}{2}

\int 7 d x = 7 x

\int \frac{4}{x} d x = 4 ln ∣ x ∣

= \frac{3 x ^{2}}{2} - 7 x + 4 ln ∣ x ∣

Add a constant to the solution

= \frac{3 x ^{2}}{2} - 7 x + 4 ln ∣ x ∣ + C

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What is the integral of (3x^2-7x+4)/x ?
The integral of (3x^2-7x+4)/x is (3x^2)/2-7x+4ln|x|+C