What is the integral of sin^8(c)osx ?

The integral of sin^8(c)osx is (osx^2sin^8(c))/2+C

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integral of sin^8(c)osx

\int sin^{8} (c) os x d x

\frac{os x ^{2} sin ^{8} ( c )}{2} + C

Solution steps

\int sin^{8} (c) os x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= sin^{8} (c) os \cdot \int x d x

Apply the Power Rule

: \frac{x ^{2}}{2}

= sin^{8} (c) os \frac{x ^{2}}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{os x ^{2} sin ^{8} ( c )}{2}

Add a constant to the solution

= \frac{os x ^{2} sin ^{8} ( c )}{2} + C

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What is the integral of sin^8(c)osx ?
The integral of sin^8(c)osx is (osx^2sin^8(c))/2+C