What is the integral of (sqrt(ln(x+1)))/(x+1) ?

The integral of (sqrt(ln(x+1)))/(x+1) is 2/3 ln^{3/2}(x+1)+C

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integral of (sqrt(ln(x+1)))/(x+1)

\int \frac{ln ( x + 1 )}{x + 1} d x

\frac{2}{3} ln^{\frac{3}{2}} (x + 1) + C

Solution steps

\int \frac{ln ( x + 1 )}{x + 1} d x

Apply u-substitution

: \int \frac{ln ( u )}{u} d u

= \int \frac{ln ( u )}{u} d u

Apply u-substitution

: \int v d v

= \int v d v

Apply the Power Rule

: \frac{2}{3} v^{\frac{3}{2}}

= \frac{2}{3} v^{\frac{3}{2}}

Substitute back

= \frac{2}{3} ln^{\frac{3}{2}} (x + 1)

Add a constant to the solution

= \frac{2}{3} ln^{\frac{3}{2}} (x + 1) + C

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What is the integral of (sqrt(ln(x+1)))/(x+1) ?
The integral of (sqrt(ln(x+1)))/(x+1) is 2/3 ln^{3/2}(x+1)+C