What is the integral of (2x^2-3x+5) ?

The integral of (2x^2-3x+5) is (2x^3)/3-(3x^2)/2+5x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (2x^2-3x+5)

\int (2 x^{2} - 3 x + 5) d x

\frac{2 x ^{3}}{3} - \frac{3 x ^{2}}{2} + 5 x + C

Solution steps

\int 2 x^{2} - 3 x + 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x^{2} d x - \int 3 x d x + \int 5 d x

\int 2 x^{2} d x = \frac{2 x ^{3}}{3}

\int 3 x d x = \frac{3 x ^{2}}{2}

\int 5 d x = 5 x

= \frac{2 x ^{3}}{3} - \frac{3 x ^{2}}{2} + 5 x

Add a constant to the solution

= \frac{2 x ^{3}}{3} - \frac{3 x ^{2}}{2} + 5 x + C

\int \frac{x - 1}{( x ^{2} + x + 1 ) ^{2}} d x

\int \frac{- 1}{3 x} d x

\int \frac{e ^{I n x}}{x} d x

\int \frac{x ^{3}}{3 6 + x ^{4}} d x

\int sec (5 t) (sec (5 t) + tan (5 t)) d t

What is the integral of (2x^2-3x+5) ?
The integral of (2x^2-3x+5) is (2x^3)/3-(3x^2)/2+5x+C