What is the integral of 0.1e^x-0.1x ?

The integral of 0.1e^x-0.1x is 0.1e^x-0.05x^2+C

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integral of 0.1e^x-0.1x

\int 0.1 e^{x} - 0.1 x d x

0.1 e^{x} - 0.05 x^{2} + C

Solution steps

\int 0.1 e^{x} - 0.1 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 0.1 e^{x} d x - \int 0.1 x d x

\int 0.1 e^{x} d x = 0.1 e^{x}

\int 0.1 x d x = 0.05 x^{2}

= 0.1 e^{x} - 0.05 x^{2}

Add a constant to the solution

= 0.1 e^{x} - 0.05 x^{2} + C

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What is the integral of 0.1e^x-0.1x ?
The integral of 0.1e^x-0.1x is 0.1e^x-0.05x^2+C