What is the integral of 2*(ln(x))/(x^4) ?

The integral of 2*(ln(x))/(x^4) is 2(-(ln(x))/(3x^3)-1/(9x^3))+C

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integral of 2*(ln(x))/(x^4)

\int 2 \cdot \frac{ln ( x )}{x ^{4}} d x

2 (- \frac{ln ( x )}{3 x ^{3}} - \frac{1}{9 x ^{3}}) + C

Solution steps

\int 2 \cdot \frac{ln ( x )}{x ^{4}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{ln ( x )}{x ^{4}} d x

Apply Integration By Parts

: - \frac{ln ( x )}{3 x ^{3}} - \int - \frac{1}{3 x ^{4}} d x

= 2 (- \frac{ln ( x )}{3 x ^{3}} - \int - \frac{1}{3 x ^{4}} d x)

\int - \frac{1}{3 x ^{4}} d x = \frac{1}{9 x ^{3}}

= 2 (- \frac{ln ( x )}{3 x ^{3}} - \frac{1}{9 x ^{3}})

Add a constant to the solution

= 2 (- \frac{ln ( x )}{3 x ^{3}} - \frac{1}{9 x ^{3}}) + C

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What is the integral of 2*(ln(x))/(x^4) ?
The integral of 2*(ln(x))/(x^4) is 2(-(ln(x))/(3x^3)-1/(9x^3))+C