What is the integral of 2019+sec(x)tan(x)-e^x ?

The integral of 2019+sec(x)tan(x)-e^x is 2019x+sec(x)-e^x+C

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integral of 2019+sec(x)tan(x)-e^x

\int 2019 + sec (x) tan (x) - e^{x} d x

2019 x + sec (x) - e^{x} + C

Solution steps

\int 2019 + sec (x) tan (x) - e^{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2019 d x + \int sec (x) tan (x) d x - \int e^{x} d x

\int 2019 d x = 2019 x

\int sec (x) tan (x) d x = sec (x)

\int e^{x} d x = e^{x}

= 2019 x + sec (x) - e^{x}

Add a constant to the solution

= 2019 x + sec (x) - e^{x} + C

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What is the integral of 2019+sec(x)tan(x)-e^x ?
The integral of 2019+sec(x)tan(x)-e^x is 2019x+sec(x)-e^x+C