What is the integral of 4/9 x^{9/5}+C ?

The integral of 4/9 x^{9/5}+C is 10/63 x^{14/5}+Cx+C

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integral of 4/9 x^{9/5}+C

\int \frac{4}{9} x^{\frac{9}{5}} + C d x

\frac{10}{63} x^{\frac{14}{5}} + C x + C

Solution steps

\int \frac{4}{9} x^{\frac{9}{5}} + C d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{4}{9} x^{\frac{9}{5}} d x + \int C d x

\int \frac{4}{9} x^{\frac{9}{5}} d x = \frac{10}{63} x^{\frac{14}{5}}

\int C d x = C x

= \frac{10}{63} x^{\frac{14}{5}} + C x

Add a constant to the solution

= \frac{10}{63} x^{\frac{14}{5}} + C x + C

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What is the integral of 4/9 x^{9/5}+C ?
The integral of 4/9 x^{9/5}+C is 10/63 x^{14/5}+Cx+C