What is the integral of 0.5+(0.2)/(sqrt(x)) ?

The integral of 0.5+(0.2)/(sqrt(x)) is 0.5x+0.4sqrt(x)+C

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integral of 0.5+(0.2)/(sqrt(x))

\int 0.5 + \frac{0.2}{x} d x

0.5 x + 0.4 x + C

Solution steps

\int 0.5 + \frac{0.2}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 0.5 d x + \int \frac{0.2}{x} d x

\int 0.5 d x = 0.5 x

\int \frac{0.2}{x} d x = 0.4 x

= 0.5 x + 0.4 x

Add a constant to the solution

= 0.5 x + 0.4 x + C

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What is the integral of 0.5+(0.2)/(sqrt(x)) ?
The integral of 0.5+(0.2)/(sqrt(x)) is 0.5x+0.4sqrt(x)+C