What is the integral of (e^{5x})^2 ?

The integral of (e^{5x})^2 is 1/10 e^{10x}+C

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integral of (e^{5x})^2

\int (e^{5 x})^{2} d x

\frac{1}{10} e^{10 x} + C

Solution steps

\int (e^{5 x})^{2} d x

Simplify

(e^{5 x})^{2} : e^{10 x}

= \int e^{10 x} d x

Apply u-substitution

: \int e^{u} \frac{1}{10} d u

= \int e^{u} \frac{1}{10} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{10} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{10} e^{u}

Substitute back

u = 10 x

= \frac{1}{10} e^{10 x}

Add a constant to the solution

= \frac{1}{10} e^{10 x} + C

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What is the integral of (e^{5x})^2 ?
The integral of (e^{5x})^2 is 1/10 e^{10x}+C