What is the integral of 1/(v^{1/2)} ?

The integral of 1/(v^{1/2)} is 2v^{1/2}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(v^{1/2)}

\int \frac{1}{v ^{\frac{1}{2}}} d v

2 v^{\frac{1}{2}} + C

Solution steps

\int \frac{1}{v ^{\frac{1}{2}}} d v

Apply the Power Rule

: 2 v^{\frac{1}{2}}

= 2 v^{\frac{1}{2}}

Add a constant to the solution

= 2 v^{\frac{1}{2}} + C

\int \frac{( 12 x ^{2} )}{2 x + 1} d x

\int \frac{1}{1 - cos ( u )} d u

\int (3 x - 1) e^{- x} d x

\int (5 x^{7} + 2)^{3} x^{6} d x

\int (4 x - 1) (8 x^{2} - 4 x + 1)^{\frac{1}{3}} d x