What is the integral of log_{x}(x^2) ?

The integral of log_{x}(x^2) is 2x+C

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integral of log_{x}(x^2)

\int lo g_{x} (x^{2}) d x

2 x + C

Solution steps

\int lo g_{x} (x^{2}) d x

lo g_{x} (x^{2}) = 2

= \int 2 d x

Integral of a constant:

\int a d x = a x

= 2 x

Add a constant to the solution

= 2 x + C

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