What is the integral of 6x^2-4x+5 ?

The integral of 6x^2-4x+5 is 2x^3-2x^2+5x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 6x^2-4x+5

\int 6 x^{2} - 4 x + 5 d x

2 x^{3} - 2 x^{2} + 5 x + C

Solution steps

\int 6 x^{2} - 4 x + 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 6 x^{2} d x - \int 4 x d x + \int 5 d x

\int 6 x^{2} d x = 2 x^{3}

\int 4 x d x = 2 x^{2}

\int 5 d x = 5 x

= 2 x^{3} - 2 x^{2} + 5 x

Add a constant to the solution

= 2 x^{3} - 2 x^{2} + 5 x + C

\int \frac{e ^{x}}{3 1 + 2 e ^{x}} d x

\int (5 x^{4} + 6 x + \frac{1}{x ^{3}}) d x

\int - \frac{5}{2} x^{- 73} d x

\int \frac{1}{5 x 16 x ^{2} - 36} d x

\int sec (x) (tan (x))^{2} d x