What is the integral of 1/(x^{2+1)} ?

The integral of 1/(x^{2+1)} is -1/(2x^2)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(x^{2+1)}

\int \frac{1}{x ^{2 + 1}} d x

- \frac{1}{2 x ^{2}} + C

Solution steps

\int \frac{1}{x ^{2 + 1}} d x

Apply the Power Rule

: - \frac{1}{2 x ^{2}}

= - \frac{1}{2 x ^{2}}

Add a constant to the solution

= - \frac{1}{2 x ^{2}} + C

\int 4 - (x - 1)^{2} d x

\int \frac{3 x - 2}{x ^{2} + 1} d x

e^{u}

What is the integral of 1/(x^{2+1)} ?
The integral of 1/(x^{2+1)} is -1/(2x^2)+C