What is the integral of (x+1)/(2(x^2+1)) ?

The integral of (x+1)/(2(x^2+1)) is 1/2 (1/2 ln|x^2+1|+arctan(x))+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (x+1)/(2(x^2+1))

\int \frac{x + 1}{2 ( x ^{2} + 1 )} d x

\frac{1}{2} (\frac{1}{2} ln x^{2} + 1 + arctan (x)) + C

Solution steps

\int \frac{x + 1}{2 ( x ^{2} + 1 )} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{x + 1}{x ^{2} + 1} d x

Expand

\frac{x + 1}{x ^{2} + 1} : \frac{x}{x ^{2} + 1} + \frac{1}{x ^{2} + 1}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int \frac{x}{x ^{2} + 1} d x + \int \frac{1}{x ^{2} + 1} d x)

\int \frac{x}{x ^{2} + 1} d x = \frac{1}{2} ln x^{2} + 1

\int \frac{1}{x ^{2} + 1} d x = arctan (x)

= \frac{1}{2} (\frac{1}{2} ln x^{2} + 1 + arctan (x))

Add a constant to the solution

= \frac{1}{2} (\frac{1}{2} ln x^{2} + 1 + arctan (x)) + C

\int \frac{5}{θ ^{2}} cos (\frac{5}{θ}) d θ

\int (2 x - 7) d x

\int 3 x tan (x^{2}) d x

\int x tan (x^{2} + 1) d x

\int 12 x^{2} + 2 x d x

What is the integral of (x+1)/(2(x^2+1)) ?
The integral of (x+1)/(2(x^2+1)) is 1/2 (1/2 ln|x^2+1|+arctan(x))+C