What is the integral of 18sin(x) ?

The integral of 18sin(x) is -18cos(x)+C

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integral of 18sin(x)

\int 18 sin (x) d x

- 18 cos (x) + C

Solution steps

\int 18 sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 18 \cdot \int sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= 18 (- cos (x))

Simplify

= - 18 cos (x)

Add a constant to the solution

= - 18 cos (x) + C

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