What is the integral of e^{y-1} ?

The integral of e^{y-1} is e^{y-1}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{y-1}

\int e^{y - 1} d y

e^{y - 1} + C

Solution steps

\int e^{y - 1} d y

e^{y - 1} = e^{- 1} e^{y}

= \int e^{- 1} e^{y} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= e^{- 1} \cdot \int e^{y} d y

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{1}{e} \cdot \int e^{y} d y

Use the common integral:

\int e^{y} d y = e^{y}

= \frac{1}{e} e^{y}

Simplify

\frac{1}{e} e^{y} : e^{y - 1}

= e^{y - 1}

Add a constant to the solution

= e^{y - 1} + C

\int (8 x^{5} - 5 x^{4} - 3 x^{3} + 6 x^{2} - 10 x - 5) d x

\int \frac{7 x}{( 6 - x ^{2} ) ^{3}} d x

\int 3 sin (x) e^{x} d x

\int x (x - 1) (x - 3) d x

\int 200 - 4 x d x