What is the integral of (x+3)/(x^2-x) ?

The integral of (x+3)/(x^2-x) is 4ln|x-1|-3ln|x|+C

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integral of (x+3)/(x^2-x)

\int \frac{x + 3}{x ^{2} - x} d x

4 ln ∣ x - 1 ∣ - 3 ln ∣ x ∣ + C

Solution steps

\int \frac{x + 3}{x ^{2} - x} d x

Expand

\frac{x + 3}{x ^{2} - x} : \frac{x}{x ^{2} - x} + \frac{3}{x ^{2} - x}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{x}{x ^{2} - x} d x + \int \frac{3}{x ^{2} - x} d x

\int \frac{x}{x ^{2} - x} d x = ln ∣ x - 1 ∣

\int \frac{3}{x ^{2} - x} d x = 3 (- ln ∣ x ∣ + ln ∣ x - 1 ∣)

= ln ∣ x - 1 ∣ + 3 (- ln ∣ x ∣ + ln ∣ x - 1 ∣)

Simplify

ln ∣ x - 1 ∣ + 3 (- ln ∣ x ∣ + ln ∣ x - 1 ∣) : 4 ln ∣ x - 1 ∣ - 3 ln ∣ x ∣

= 4 ln ∣ x - 1 ∣ - 3 ln ∣ x ∣

Add a constant to the solution

= 4 ln ∣ x - 1 ∣ - 3 ln ∣ x ∣ + C

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What is the integral of (x+3)/(x^2-x) ?
The integral of (x+3)/(x^2-x) is 4ln|x-1|-3ln|x|+C