What is the integral of (2x+4)/(x^2+4x+5) ?

The integral of (2x+4)/(x^2+4x+5) is ln|x^2+4x+5|+C

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integral of (2x+4)/(x^2+4x+5)

\int \frac{2 x + 4}{x ^{2} + 4 x + 5} d x

ln x^{2} + 4 x + 5 + C

Solution steps

\int \frac{2 x + 4}{x ^{2} + 4 x + 5} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = x^{2} + 4 x + 5

= ln x^{2} + 4 x + 5

Add a constant to the solution

= ln x^{2} + 4 x + 5 + C

\int \frac{x ^{2} - 3 x + 2}{x ( x ^{2} + 2 x + 1 )} d x

\int (x)^{- 2} d x

\int x^{4} e^{6 x^{5}} d x

\int 3 x^{2} sin (x^{3} + 1) d x

What is the integral of (2x+4)/(x^2+4x+5) ?
The integral of (2x+4)/(x^2+4x+5) is ln|x^2+4x+5|+C